Free Angular and Linear Quantities MCQs with Answers

317 Angular and Linear Quantities MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

Rotational motion relates angular displacement, angular velocity and angular acceleration to linear displacement, tangential velocity and tangential acceleration through the radius. Questions use radians, v equals r omega and tangential acceleration, while distinguishing tangential velocity from centripetal acceleration and angular quantities from their linear counterparts.

Last updated

317 questions · page 2 of 16

  • A. At the highest point
  • B. At the lowest point
  • C. At any point during motion
  • D. At the point where gravity is not acting

Explanation: At the lowest point of a vertical circle, the stone has its greatest speed because it has lost the most gravitational potential energy.

Correct answer: At the lowest point
  • A. 1N
  • B. 10N
  • C. 2N
  • D. 100N

Explanation: The required centripetal force, often described as an apparent outward centrifugal force in the rotating frame, has magnitude F = mv2/r.

Correct answer: 1N
  • A. F=ma
  • B. F=τp/It
  • C. Στ = I α
  • D. All above

Explanation: The rotational form of Newton’s second law is Στ = Iα, where torque is the rotational equivalent of force, moment of inertia is the…

Correct answer: Στ = I α
  • A. the centripetal force upon him is less than limiting friction
  • B. the centripetal force upon him is greater than limiting friction
  • C. the centripetal force upon him is equal to the limiting friction
  • D. the friction between the tyres of the cycle and road vanishes

Explanation: For circular motion, static friction supplies the required centripetal force up to its limiting value.

Correct answer: the centripetal force upon him is greater than limiting friction
  • A. 2π
  • B. π/2
  • C. π
  • D. 20π

Explanation: The wheel's circumference is πd = π x 1 m = π m, and 30 revolutions per minute equals 0.5 revolutions per second.

Correct answer: π/2
  • A. Gravitational force
  • B. Frictional force
  • C. Coulomb force
  • D. Centripetal force

Explanation: A planet needs centripetal acceleration to remain in orbit, and the gravitational force of the Sun provides this inward force.

Correct answer: Gravitational force
  • A. mV/r2
  • B. mV/r
  • C. mV2/r
  • D. mV2/r2

Explanation: For circular motion, the required centripetal acceleration is v²/r, so Newton's second law gives F = m(v²/r) = mV²/r.

Correct answer: mV2/r
  • A. Mass of a body
  • B. Velocity of body
  • C. The tension in the string
  • D. Centripetal acceleration

Explanation: In horizontal circular motion, the inward force required for centripetal acceleration is supplied by the string's tension.

Correct answer: The tension in the string
  • A. WA. 180°
  • B. 0°
  • C. 90°
  • D. 45°

Explanation: For circular motion, linear velocity is tangent to the path, while angular velocity points along the rotation axis.

Correct answer: 90°
  • A. along the axis of rotation
  • B. along the tangent
  • C. directed towards the centre
  • D. directed away from the centre

Explanation: The instantaneous linear velocity of a point on a circular path is tangent to the circle at that point.

Correct answer: along the tangent
  • A. T = πv
  • B. T = πw
  • C. T = 2πr
  • D. T = 2πr/v

Explanation: The period is the time for one revolution, whose distance is the circumference 2πr m.

Correct answer: T = 2πr/v
  • A. 42000km
  • B. 36000km
  • C. 24000 km
  • D. 18000 km

Explanation: A geostationary orbit has an orbital radius of about 42,000 km measured from Earth's centre.

Correct answer: 42000km
  • A. 3 hours
  • B. 6 hours
  • C. 12 hours
  • D. 24 hours

Explanation: A geostationary satellite must have the same angular speed as Earth's rotation, completing one revolution in Earth's rotational period.

Correct answer: 24 hours
  • A. 8 Kms-1
  • B. 8.1 Kms-1
  • C. 7.9 Kms-1
  • D. 8 ms-1

Explanation: The speed needed for a low Earth satellite is v = √(GM/r), which gives approximately 7.9 km s-1 near Earth's surface.

Correct answer: 7.9 Kms-1
  • A. Acceleration
  • B. Linear acceleration
  • C. Angular acceleration
  • D. Direction of motion of the body

Explanation: Torque is the rotational analogue of force and produces angular acceleration according to τ = Iα, where τ is torque in N m, I is moment of…

Correct answer: Angular acceleration
  • A. N.m
  • B. joule
  • C. Both a and b are correct
  • D. Neither a nor b is correct

Explanation: Torque equals force multiplied by perpendicular distance, so its SI unit is N m: N x m = kg m s^-2 x m = kg m² s^-2.

Correct answer: N.m
  • A. [ML2T-2]
  • B. [MLT-2]
  • C. [ML2T]
  • D. [ML-2T-2]

Explanation: Torque is force multiplied by distance, so its dimensions are [MLT^-2] x [L] = [ML2T^-2].

Correct answer: [ML2T-2]
  • A. Can produce torque
  • B. Cannot produce torque
  • C. Some time can produce torque some time cannot
  • D. Has no relation with torque

Explanation: A central force acts along the line joining the body to the centre, so the position vector and force are parallel.

Correct answer: Cannot produce torque
  • A. Accelerating force increases on the wheel
  • B. Two forces act on the wheel
  • C. Two hands provide a firm grip
  • D. The couple acts on the wheel

Explanation: Using both hands can produce a couple, in which two equal and opposite forces act along different lines and create a turning effect.

Correct answer: The couple acts on the wheel
  • A. Torque and energy
  • B. Momentum and impulse
  • C. Energy and work
  • D. Mass and moment of inertia

Explanation: Torque and energy both have dimensions ML²T^-2, momentum and impulse both have dimensions MLT^-1, and energy and work both have dimensions…

Correct answer: Mass and moment of inertia