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All Free Mathematics MCQs with Answers

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1,551 questions · page 45 of 78

881. 605 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20 % of the total number of children. How many sweets did each child receive?

  • A. 11
  • B. 24
  • C. 45
  • D. cannot be determined

Explanation: Let the number of children be n. Each child receives 20% of n = 0.2n sweets, so the total is n × 0.2n = 605; hence n² = 3,025 and n = 55…

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Correct answer: 11

882. If eggs cost $.06 each ,how much should a dozen eggs cost ?

  • A. .56
  • B. $ .80
  • C. $ .72
  • D. $.60Education

Explanation: A dozen contains 12 eggs, so the cost is 12 x $0.06 = $0.72. Option d, $0.60, results from multiplying by 10 instead of recognising that a…

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Correct answer: $ .72

883. Two-fifth of one-third of three-seventh of a number is 15. What is 40% of that number?

  • A. 72
  • B. 84
  • C. 136
  • D. 140
  • E. None of these

Explanation: The given fraction is (2/5) x (1/3) x (3/7) = 2/35, so (2/35)n = 15 and n = 15 x 35/2 = 262.5.

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Correct answer: None of these

884. The ratio of the prices of three articles X, Y and Z is 8 : 5 : 3. If the prices of X , Y and Z are increased by 25%, 20% and 33 1/3% respectively, then what would be the ratio of the new prices of X, Y and Z?

  • A. 5 : 3 : 1
  • B. 5 : 3 : 2
  • C. 10 : 7 : 4
  • D. 10 : 8 : 5
  • E. None of these

Explanation: Apply each increase to the original ratio: X = 8 x 1.25 = 10, Y = 5 x 1.20 = 6, and Z = 3 x 4/3 = 4.

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Correct answer: 5 : 3 : 2

885. The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 15000, then find the annual income of A?

  • A. Rs. 420000
  • B. Rs. 180000
  • C. Rs. 201600
  • D. Rs. 504000
  • E. None of these

Explanation: C earns Rs. 15000 per month, so B earns 112% of this: 1.12 x Rs. 15000 = Rs. 16800 per month. Since A:B = 5:2, A earns (5/2) x Rs.

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Correct answer: Rs. 504000

886. There are three numbers. 5/7th of the first number is equal to 48% of the second number. The second number is 1/9th of the third number. If the third number is 1125, then find 25% of the first number?

  • A. 168
  • B. 84
  • C. 42
  • D. 21
  • E. None of these

Explanation: The third number is 1125, so the second is 1125 / 9 = 125. Then 48% of 125 = 60, so (5/7) of the first number is 60 and the first number…

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Correct answer: 21

887. There are two numbers. If 40% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?

  • A. 8 : 25
  • B. 25 : 8
  • C. 8 : 5
  • D. 5 : 8
  • E. None of these

Explanation: Let the first and second numbers be x and y. The condition gives y + 0.40x = 1.25y, so 0.40x = 0.25y and x:y = 0.25:0.40 = 5:8; option c…

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Correct answer: 5 : 8

888. If two positive numbers are in the ratio 1/8 : 1/5, then by what percent is the second number more than the first?

  • A. 40%
  • B. 33 1/3%
  • C. 60%
  • D. 66 2/3%
  • E. None of these

Explanation: The ratio 1/8 : 1/5 becomes 5 : 8 after multiplying both terms by 40. The second number exceeds the first by 3 parts, so the percentage…

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Correct answer: 60%

889. In what ratio should the profit be divided if M, N, O invests capital in ratio 2:3:5 and their timing of their investments are in the ratio 4:5:6.

  • A. 8:15:30
  • B. 5:18:28
  • C. 4:5:6
  • D. 2:3:5

Explanation: Profit is divided according to capital multiplied by investment time. Thus the ratio is (2 × 4):(3 × 5):(5 × 6) = 8:15:30.

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Correct answer: 8:15:30

890. A bag contains 50 paise, 1 rupee and 2 rupee coins in the ratio 2:5:8. If the total amount is Rs. 352, find the total number of coins in the bag.

  • A. 160
  • B. 200
  • C. 250
  • D. 240

Explanation: Let the numbers of 50-paise, 1-rupee and 2-rupee coins be 2k, 5k and 8k. Their value is Rs. (0.50 × 2k) + (1 × 5k) + (2 × 8k) = Rs.

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Correct answer: 240

891. Three quantities X, Y and Z are such that XY=kZ where k is constant. Initially, X was at 4 and X:Y:Z was 2:3:4. If the value of Y is changed to 12 and Z is kept constant, find the value of X.

  • A. 2
  • B. 3
  • C. 5
  • D. 6

Explanation: Initially, X:Y:Z = 2:3:4 and X = 4, so one ratio unit is 2 and the initial values are Y = 6 and Z = 8.

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Correct answer: 2

892. Find the mean proportion between 5 and 45.

  • A. 9
  • B. 15
  • C. 25
  • D. 50

Explanation: The mean proportion between 5 and 45 is their geometric mean, √(5 × 45) = √225 = 15.

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Correct answer: 15

893. If X:Y = 2:3, Y:Z = 4:5. Find X:Y:Z.

  • A. 2:3:5
  • B. 8:12:15
  • C. 2:8:5
  • D. 2:7:5

Explanation: Make the common term Y equal in both ratios: X:Y = 2:3 becomes 8:12, and Y:Z = 4:5 becomes 12:15. Therefore, X:Y:Z = 8:12:15.

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Correct answer: 8:12:15

894. The ratio of two numbers a and b is 3:5. If 2 is added to both the numbers, the ratio becomes 2:3. Find b.

  • A. 15
  • B. 10
  • C. 8
  • D. 5

Explanation: Let a = 3k and b = 5k. After adding 2 to each number, (3k + 2):(5k + 2) = 2:3, so 3(3k + 2) = 2(5k + 2), giving 9k + 6 = 10k + 4 and k =…

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Correct answer: 10

895. M:N = 3:4, N:O = 5:7 and O:P = 7:9. Then M:P =________?

  • A. 1/3
  • B. 7/9
  • C. 5/12
  • D. None of these

Explanation: Multiply the linked ratios: M:P = (M:N) × (N:O) × (O:P) = (3/4) × (5/7) × (7/9) = 15/36 = 5/12.

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Correct answer: 5/12

896. The perimeter of a triangle is 81 cm. If the sides are in the ratio 4:3:2, find the length of the largest side.

  • A. 45 cm
  • B. 40 cm
  • C. 36 cm
  • D. 27 cm

Explanation: The ratio has 4 + 3 + 2 = 9 parts, so each part is 81 cm ÷ 9 = 9 cm. The largest side is 4 parts, giving 4 × 9 cm = 36 cm.

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Correct answer: 36 cm

897. The ratio of boys and girls in a class was 11:13. 8 girls and 4 boys join the class from this academic year and the ratio becomes 4:5. Find the strength of the class.

  • A. 96
  • B. 68
  • C. 72
  • D. 108

Explanation: Let the original numbers be 11k boys and 13k girls. After the additions, (11k + 4):(13k + 8) = 4:5, so 5(11k + 4) = 4(13k + 8), giving k =…

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Correct answer: 108

898. A class has 90 students. If the ratio of boys and girls is 7:8, find the number of boys in the class.

  • A. 48
  • B. 42
  • C. 60
  • D. 70

Explanation: The total ratio parts are 7 + 8 = 15, so one part represents 90 students ÷ 15 = 6 students. Boys = 7 × 6 students = 42 students.

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Correct answer: 42

899. A bag contains 1 rupee, 2 rupee and 5 rupee coins amounting to Rs.264. If the ratio of the number of these coins is 3:5:4, find the number of 1 rupee coins.

  • A. 66
  • B. 48
  • C. 24
  • D. 8

Explanation: Let the coin counts be 3k, 5k and 4k. Their total value is 1(3k) + 2(5k) + 5(4k) rupees = 33k rupees, so 33k = Rs.264 and k = 8; the…

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Correct answer: 24

900. Divide Rs.2000 into two shares in the ratio 3:2.

  • A. Rs.1200,Rs.800
  • B. Rs.800,Rs.1200
  • C. Rs.1500,Rs.500
  • D. Rs.1100, Rs.900

Explanation: The ratio contains 3 + 2 = 5 parts, so each part is Rs.2000 ÷ 5 = Rs.400. The two shares are 3 × Rs.400 = Rs.1200 and 2 × Rs.400 = Rs.800.

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Correct answer: Rs.1200,Rs.800
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