All Free Electrical Engineering MCQs with Answers

Every Electrical Engineering question in the bank, across all chapters, each with the correct answer and a written explanation. Free and unlimited, with no account needed.

3,143 questions · page 55 of 158

  • A. improve power factor
  • B. increase overload capacity
  • C. reduce fluctuations in torque
  • D. to improve torque

Explanation: The running capacitor remains in circuit and provides the required phase shift for the auxiliary winding, improving the motor's running…

Correct answer: improve power factor
  • A. high resistance and low inductance
  • B. low resistance and high inductance
  • C. high resistance as well as high inductance
  • D. low resistance as well as low inductiance

Explanation: The running winding is designed with low resistance and relatively high inductance, giving it a better power factor during normal…

Correct answer: low resistance and high inductance
  • A. current in the starting winding leads the voltage
  • B. current in the starting winding lags the voltage
  • C. current in the starting winding is in phase with voltage in running winding
  • D. none of the above

Explanation: The capacitor in series with the starting winding makes its current lead the applied voltage, producing the phase difference needed for…

Correct answer: current in the starting winding leads the voltage
  • A. 10°
  • B. 30°
  • C. 60°
  • D. 90°

Explanation: A capacitor-start motor is designed to produce a large phase difference between the starting and running winding currents, approaching…

Correct answer: 90°
  • A. Capacitor start motor
  • B. Capacitor run motor
  • C. Split phase motor
  • D. Shaded pole motor

Explanation: The capacitor-start motor has relatively high starting torque because its capacitor produces a large phase displacement between the two…

Correct answer: Capacitor start motor
  • A. increases the load torque
  • B. decreases the starting torque
  • C. increases the starting torque
  • D. none of the above

Explanation: Adding resistance in the stator causes a voltage drop, so the motor receives a lower voltage and its starting torque decreases…

Correct answer: decreases the starting torque
  • A. synchronous speed
  • B. below synchronous speed
  • C. above synchronous speed
  • D. any of the above

Explanation: An induction motor must have positive slip to induce rotor current and produce torque, so its rotor speed remains slightly below…

Correct answer: below synchronous speed
  • A. high starting torque is required
  • B. load torque is heavy
  • C. heavy pull out torque is required
  • D. all of the above

Explanation: A slip-ring motor permits external rotor resistance to be added during starting, allowing high starting torque with controlled current.

Correct answer: high starting torque is required
  • A. slip ring motor only but not with squirrel cage induction motor
  • B. squirrel cage induction motor only but not with slip ring motor
  • C. squirrel cage as well as slip ring induction motor
  • D. none of the above

Explanation: Reduced-voltage starting methods can be applied to both squirrel-cage and slip-ring induction motors, although slip-ring motors also allow…

Correct answer: squirrel cage as well as slip ring induction motor
  • A. initial cost is the main consideration
  • B. maintenance cost is to be kept low
  • C. higher starting torque is the main consideration
  • D. all above considerations are involved

Explanation: A squirrel-cage motor has low starting torque because its rotor resistance cannot be externally increased.

Correct answer: higher starting torque is the main consideration
  • A. slip ring induction motor
  • B. squirrel cage induction motor
  • C. both A. and (b)
  • D. none of the above

Explanation: The squirrel-cage rotor has no slip rings, brushes, or external starting equipment, so it needs less maintenance than a slip-ring motor.

Correct answer: squirrel cage induction motor
  • A. dependent on the shaft loading
  • B. dependent on the number of slots
  • C. slip times the stand still e.m.f. induced in the rotor
  • D. none of the above

Explanation: Rotor frequency and induced rotor emf are proportional to slip; therefore, rotor emf at running condition is s times the standstill rotor…

Correct answer: slip times the stand still e.m.f. induced in the rotor
  • A. to short circuit the rotor at slip rings
  • B. to short circuit the starting resistances in the starter
  • C. to short circuit the stator phase of motor to form star
  • D. none of the above

Explanation: After the motor accelerates, the starting resistance of a slip-ring motor is removed by short-circuiting the rotor slip rings.

Correct answer: to short circuit the rotor at slip rings
  • A. slip ring type
  • B. squirrel cage type
  • C. any of the above
  • D. none of the above

Explanation: A slip-ring induction motor is preferred for high-inertia loads because external rotor resistance provides high starting torque with…

Correct answer: slip ring type
  • A. decreases the rotor current
  • B. increases the rotor current
  • C. rotor current becomes zero
  • D. rotor current rernains same

Explanation: For a specified torque, the required rotor current is essentially fixed; adding rotor resistance mainly increases slip and lowers the…

Correct answer: rotor current rernains same
  • A. it is run on load
  • B. it is run in reverse direction
  • C. it is run on voltage higher than the rated voltage
  • D. e.m.f. is injected in the rotor circuit

Explanation: At synchronous speed, slip and the naturally induced rotor emf are zero, so an ordinary induction motor cannot produce torque there.

Correct answer: e.m.f. is injected in the rotor circuit
  • A. rotor leakage reactance
  • B. stator reactance
  • C. the reactive lagging magnetizing current necessary to generate the magnetic flux
  • D. all of the above

Explanation: The dominant cause is the lagging magnetizing current needed to establish air-gap flux; stator and rotor leakage reactances also add…

Correct answer: all of the above
  • A. supply frequency
  • B. supply voltage
  • C. copper losses in motor
  • D. none of the above

Explanation: Slip equals rotor copper loss divided by rotor input power, so it changes with the rotor copper loss as the load changes.

Correct answer: copper losses in motor
  • A. sR2X2 = 1
  • B. sR2 = X2
  • C. R2 = sX2
  • D. R2 = s2X2

Explanation: For maximum torque during running, the slip-dependent rotor reactance equals the rotor resistance: sX2 = R2.

Correct answer: R2 = sX2
  • A. high inductance arid low resistance
  • B. low inductance and high resistance
  • C. low inductance and low resistance
  • D. high inductance and high resistance

Explanation: The inner cage is designed for running performance, so it uses low resistance and deep bars that give high leakage inductance.

Correct answer: high inductance arid low resistance