Free s-Block and p-Block Elements MCQs with Answers
1,359 s-Block and p-Block Elements MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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1,359 questions · page 17 of 68
- A. Metallic hydrides
- B. Complex hydrides
- C. Polymeric hydrides
- D. Borderline hydrides
Explanation: ZnH₂ does not exist as simple Zn-H units.Instead, it forms a polymeric structure where hydrogen atoms act as bridges between zinc atoms…
Correct answer: Polymeric hydrides- A. 1.60 and 1.60
- B. 0.72 and 1.60
- C. 0.72 and 0.72
- D. None of these
Explanation: The atomic radius of Fluorine is its covalent radius, which is small (~0.72 Å).
Correct answer: 0.72 and 1.60- A. Normal elements
- B. Transition elements
- C. Lanthanides
- D. Actinides
Explanation: The lanthanide series, also known as the lanthanoids, is the block of 14 elements following Lanthanum (Z=57) in the periodic table.
Correct answer: Lanthanides- A. Mg(g) → Mg+(g) + e-
- B. Mg+(g)→ Mg2+(g)+ e-
- C. Na(g)→ Na+ (g)+ e-
- D. Na+(g)→ Na2+(g)+ e-
Explanation: This process represents the second ionization of Sodium. After the first ionization, Na⁺ has a very stable, noble gas electron…
Correct answer: Na+(g)→ Na2+(g)+ e-- A. Li < Na < K < Rb < Cs
- B. Cs < K < Rb < Na < Li
- C. Na < K < Rb < Cs < Li
- D. K < Na < Rb < Cs < Li
Explanation: Reducing power generally increases down the group due to decreasing ionization energy.
Correct answer: Na < K < Rb < Cs < Li- A. It forms a basic oxide
- B. It belongs to Group 2 (IIA)
- C. It belongs to Period 4
- D. It forms an acidic oxide
Explanation: The element with this configuration is Calcium (Ca), an alkaline earth metal. As a metal, it forms a basic oxide (CaO).
Correct answer: It forms an acidic oxide- A. d5, d3, d1, d4 - increasing magnetic moment
- B. MO, M2O3, MO2, M2O5 - decreasing basic strength
- C. Sc, V, Cr, Mn - increasing number of oxidation states
- D. Co2+, Fe3+, Cr3+, Sc3+ - increasing stability
Explanation: Magnetic moment is proportional to the number of unpaired electrons. The number of unpaired electrons for these configurations is 5, 3, 1…
Correct answer: d5, d3, d1, d4 - increasing magnetic moment- A. Na2O > MgO > Al2O3 > CuO
- B. MgO > Al2O3 > CuO > Na2O
- C. Al2O3 > MgO > CuO > Na2O
- D. CuO > Na2O > MgO > Al2O3
Explanation: The basic character of oxides decreases across a period as metallic character decreases.
Correct answer: Na2O > MgO > Al2O3 > CuO- A. Only alkali metals
- B. Only transition elements
- C. Only noble gases
- D. None of the above
Explanation: Non-stoichiometric compounds are formed by transition elements because they show variable oxidation states and defects in crystal…
Correct answer: Only transition elements- A. 3, 11, 19, 37
- B. 5, 13, 21, 39
- C. 7, 15, 31, 49
- D. 5, 13, 31, 49
Explanation: Group 13 begins with Boron (Z=5). The atomic numbers of subsequent elements are found by adding 8, 18, 18, etc.
Correct answer: 5, 13, 31, 49- A. Group 1 (IA)
- B. Group 13 (IIIA)
- C. Group 3 (IIIB)
- D. Group 18 (Zero Group)
Explanation: Group 3 is unique because it contains not only the four d- block elements (Sc, Y, Lu, Lr) but also serves as the placeholder for the two…
Correct answer: Group 3 (IIIB)- A. Increasing atomic number
- B. Decreasing atomic number
- C. Increasing atomic mass
- D. Decreasing atomic mass
Explanation: The modern periodic table is organized based on the Modern Periodic Law, which states that the properties of elements are a periodic…
Correct answer: Increasing atomic number- A. Mg(OH)2
- B. Ca(OH)2
- C. Sr(OH)2
- D. Ba(OH)2
Explanation: For the hydroxides of the alkaline earth metals (Group 2), solubility in water increases as you move down the group.
Correct answer: Ba(OH)2- A. MgO and NO2
- B. Mg and NO2
- C. MgO, NO2 and O2
- D. Mg(NO3)2
Explanation: Since magnesium nitrate has a high affinity for water, heating the hexahydrate does not result in the dehydration of the salt, but rather…
Correct answer: MgO, NO2 and O2- A. O2
- B. NO2
- C. O2 + NO2
- D. NaNO2 + O2
Explanation: Sodium nitrate (and potassium nitrate) upon heating decomposes to produce sodium nitrite and colorless and odourless oxygen gas.
Correct answer: NaNO2 + O2- A. Ionization energy
- B. Melting point
- C. Ionic radius
- D. Atomic radius
Explanation: Na, Mg, Al, Si are all GIANT LATTICE structures involving either metallic (Na, Mg, Al) or giant covalent macromolecule (Si) bonding.
Correct answer: Melting point- A. 12 C 6
- B. 14 N 7
- C. 16 O 7
- D. 19F 9
Explanation: EA increases (more negative value) along the period (→). But there is an exception in EA's value of N and C.
Correct answer: 14 N 7- A. Mendeleev's periodic law
- B. Newland's law of octaves
- C. Dobereiner's triads
- D. Lothar Meyer's classification
- E. Modern periodic law
Explanation: The modern Periodic law can be stated as: "The physical and chemical properties of the elements are periodic functions of their atomic…
Correct answer: Modern periodic law- A. They belong to 18th group of the modern periodic table.
- B. Except Rn, all the remaining noble gases are present in the air.
- C. These elements belong to 17th group in the IUPAC system.
- D. These are highly reactive elements.
- E. None of the above
Explanation: Noble gases are elements located in the 18th group of the modern periodic table.
Correct answer: They belong to 18th group of the modern periodic table.- A. Ortho-bromotoluene and meta-bromotoluene
- B. Meta-bromotoluene and para-bromotoluene
- C. Ortho-bromotoluene and para-bromotoluene
- D. Ortho-bromotoluene and ortho-bromotoluene
- E. Para-bromotoluene and para-bromotoluene
Explanation: The correct answer is Ortho-bromotoluene and para-bromotoluene. The methyl group (-CH3) on the benzene ring acts as an ortho-para…
Correct answer: Ortho-bromotoluene and para-bromotoluene