Free Chemistry of Hydrocarbons MCQs with Answers

1,091 Chemistry of Hydrocarbons MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.

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1,091 questions · page 33 of 55

  • A. RNa+
  • B. RCO+
  • C. RCOO+
  • D. RNO+

Explanation: Acylium ions are cations of the formula RCO +. The carbon-oxygen bond length in these cations is near 1.1 Å (110-112 pm), which is shorter…

Correct answer: RCO+
  • A. C2H6
  • B. C2H4
  • C. C2H2
  • D. C3H6

Explanation: In alkynes,terminal alkyne has acidic hydrogen due to the high level of s character in the sp hybrid orbital, which bonds with the s…

Correct answer: C2H2
  • A. E1 and E2
  • B. E1 and SN1
  • C. SN1 and SN2
  • D. E2and SN1

Explanation: E1 (unimolecular elimination) and SN1 (unimolecular nucleophilic substitution) both involve the same first step: the formation of a…

Correct answer: E1 and SN1
  • A. Functional group isomers
  • B. Metamers
  • C. Position isomers
  • D. Tautomers

Explanation: Propylene glycol and trimethylene glycol are positional isomers. In positional isomers, the same molecular formula is retained, but the…

Correct answer: Position isomers
  • A. Only 2-butene
  • B. Only 1-butene
  • C. 2-butene as the major product
  • D. 1-butene as the major product

Explanation: In the dehydrohalogenation of 2-bromobutane with alcoholic KOH, the elimination reaction follows Zaitsev's rule, where the more…

Correct answer: 2-butene as the major product
  • A. Activates the benzene ring towards electrophilic aromatic substitution
  • B. Deactivates the benzene ring towards electrophilic aromatic substitution
  • C. Has no effect on the reactivity of the benzene ring
  • D. Makes the benzene ring more reactive towards nucleophilic aromatic substitution

Explanation: he -NH₃⁺ group is a strongly electron-withdrawing, deactivating group.It reduces the ring's reactivity and directs substituents to the…

Correct answer: Deactivates the benzene ring towards electrophilic aromatic substitution
  • A. Dehydrohalogenation of vicinal dihalide
  • B. Hydrogenation of alkene
  • C. Hydrolysis
  • D. Hydration of alkene

Explanation: Dehydrohalogenation is a reaction where a vicinal dihalide (a compound with two halogen atoms on adjacent carbon atoms) is converted into…

Correct answer: Dehydrohalogenation of vicinal dihalide
  • A. Propanal
  • B. Propanone
  • C. Methyl ethyl ether
  • D. Butanone

Explanation: Propenol (CH₃CH=CHOH) is a tautomer of propanone (CH₃COCH₃), also known as acetone.

Correct answer: Propanone
  • A. NO2
  • B. COOH
  • C. Cl
  • D. NH3

Explanation: A ring deactivator is a substituent that reduces the reactivity of the benzene ring towards electrophilic substitution reactions.

Correct answer: NO2
  • A. Methylene chloride
  • B. Carbon tetrachloride
  • C. Methylene dichloride
  • D. Chloroform

Explanation: The chlorination of methane in the presence of UV light and excess chlorine is a substitution reaction that proceeds through a series of…

Correct answer: Carbon tetrachloride
  • A. 2-Bromo-4-chloro-3-lodopentane
  • B. 4-Bromo-2-chloro-3-lodopentane
  • C. 4 Bromo-2 iodo-3-chloropentane
  • D. 2-Chloro-3-iodo-4-bromopentane

Explanation: The IUPAC name is determined by the following rules:1. Number the carbon atoms in the chain, starting from the end closest to the…

Correct answer: 2-Bromo-4-chloro-3-lodopentane
  • A. C3H8
  • B. C2H6
  • C. C2H4
  • D. C2H2

Explanation: The bond lengths in the given molecules are:- C3H8 (propane): 1.54 Å (single bond)- C2H6 (ethane): 1.53 Å (single bond)- C2H4 (ethylene)…

Correct answer: C2H2
  • A. Cis Isomers
  • B. Trans Isomers
  • C. Optical Isomers
  • D. Geometric isomers

Explanation: Enantiomers are pairs of molecules that are mirror images of each other, but are not superimposable.

Correct answer: Optical Isomers
  • A. Electrons that are free to move around the molecule in the π bonding system above and below the plane of the carbon atoms in the benzene ring
  • B. Electrons that are not free to move around the molecule in the π bonding system above and below the plane of the carbon atoms in the benzene ring
  • C. Electrons that are free to move around the molecule in the σ bonding system above and below the plane of the carbon atoms in the benzene ring
  • D. Electrons that are free to move around the molecule in the π bonding in the benzene ring

Explanation: Electrons that are free to move around the molecule in the π bonding system above and below the plane of the carbon atoms in the benzene…

Correct answer: Electrons that are free to move around the molecule in the π bonding system above and below the plane of the carbon atoms in the benzene ring
  • A. One
  • B. Two
  • C. Three
  • D. Four - Incorrect. Isobutane does not have four primary carbon atoms.

Explanation: Three - Correct. Isobutane (C₄H₁₀) has three primary carbon atoms, each bonded to only one other carbon.

Correct answer: Three
  • A. Phenanthrene
  • B. Triphenylmethane
  • C. Diphenyl ether
  • D. Anthracene

Explanation: Anthracene consists of three linearly fused benzene rings, making it a polycyclic aromatic hydrocarbon.

Correct answer: Anthracene
  • A. R-CO-R
  • B. R-CO-OR
  • C. R-CO-OH
  • D. R-COO-R

Explanation: R-CO-OR is the functional group of an ester, which consists of a carbonyl group bonded to an oxygen attached to another alkyl or aryl group.

Correct answer: R-CO-OR
  • A. Malonic acid
  • B. Maleic acid
  • C. Succinic acid
  • D. Lactic acid

Explanation: Maleic acid has a C=C double bond with carboxyl groups attached, allowing for cis-trans isomerism.

Correct answer: Maleic acid
  • A. dsp3
  • B. sp
  • C. sp3
  • D. dps3
  • E. sp2

Explanation: In an ethene molecule, the carbon atoms are sp2 hybridized. One unpaired electron in the p orbital remains unchanged.

Correct answer: sp2
  • A. Dehydrohalogenation
  • B. Wurtz reaction
  • C. Dehydration
  • D. Catalytic dehydrogenation
  • E. Dehalogenation

Explanation: The reaction you described, where 2-chloropropane is heated with Na metal to produce 2,3-dimethyl butane, is a Wurtz reaction.

Correct answer: Wurtz reaction