Free Alkyl Halides MCQs with Answers
458 Alkyl Halides MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Alkyl halides are named and related to their carbon-halogen structure, polarity and reactivity. The key reactions are nucleophilic substitution by SN1 and SN2 mechanisms and elimination by E1 and E2 mechanisms, including how substrate structure, nucleophile, base, solvent and temperature influence substitution versus elimination.
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Read the Alkyl Halides notesFree MDCAT chapter notes with key terms458 questions · page 14 of 23
- A. Ar-I
- B. Ar-Cl
- C. Ar-F
- D. Ar-Br
Explanation: Since F is most electronegative it will increase the positive charge density on ring carbon atom and will also stabilize the resulting…
Correct answer: Ar-F- A. IV > III > I > II
- B. I > II > IV > III
- C. I > III > IV > II
- D. III > II > I > IV
Explanation: I : most stable. From the double bonds, we can see that the strcture is stabilized due to stable delocalization and distribution of pi…
Correct answer: I > III > IV > II263. Towards nucleophilic substitution reaction with KNH2 in liquid NH3, the more reactive substrate is :
- A. C6H5-CH2-Cl
- B. C6H5-Cl
- C. t-Bu-Cl
- D. C6H5-CH = CH-Cl
Explanation: The Cl is attached to the alkyl group attached to the main ring, thus it is not directyl attached to the main ring.
Correct answer: C6H5-CH2-Cl- A. Option A
- B. Option B
- C. Option C
- D. Option D
Explanation: The correct option is C If carbocation can't undergo rearrangement then SN1 and SN2 product is same.
Correct answer: Option C- A. I > II > III
- B. III > II > I
- C. II > I > III
- D. None
Explanation: We know that a species that donates a pair of electrons to form a chemical bond is known as a nucleophile.
Correct answer: III > II > I- A. Option A
- B. Option B
- C. Option C
- D. Option D
Explanation: As we know, Bulky base favours Hofmann elimination. Hence, option C is correct.
Correct answer: Option C- A. -I
- B. -Cl
- C. -Br
- D. -F
Explanation: Greater the tendency of the leaving group, greater is the formation of Saytzeff's product.
Correct answer: -I- A. Addition-elimination mechanism
- B. Elimination-addition mechanism
- C. Benzyne mechanism
- D. Both (b) and (c)
Explanation: This reaction will follow both elimination-addition and benzyne mechanism as shown below.
Correct answer: Both (b) and (c)- A. An enantiomer of the substrate.
- B. A product with opposite optical rotation.
- C. A mixture of diastereomers.
- D. A single stereoisomer.
Explanation: SN2 reaction proceeds with inversion of configuration. Since the attacking nucleophile is not same as that of leaving group, the product…
Correct answer: A single stereoisomer.- A. 3−methyl−2−butanol
- B. 2−methyl−2−butanol
- C. 3−methylbutanol
- D. 1−methylbutanol
Explanation: The intermediate is a 2° carbocation which rearranges to a more stable 3° carbocation by the shift of hydride.
Correct answer: 2−methyl−2−butanol- A. I > II > III > IV
- B. IV > III > I > II
- C. III > II > I > IV
- D. II > III > IV > I
Explanation: Weaker the base, better is the leaving group. Hence, basicities decrease in the order.
Correct answer: IV > III > I > II- A. An enantiomer of the substance
- B. A product with opposite optical rotation
- C. A mixture of diastereomers
- D. A single stereoisomer
Explanation: In SN2 reaction, inversion of configuration occurs. Since the reactant and the product are not enantiomers, the sign of optical rotation…
Correct answer: A single stereoisomer- A. CH3CH2CH2CH2Cl
- B. CH3CH(Cl) CH2CH3
- C. (CH3)2 CHCH2Cl
- D. (CH3)3CCl
Explanation: As we have already mentioned that hydrolysis of 3° alkyl halide is independent of nucleophilic concentration.
Correct answer: (CH3)3CCl- A. 2sp3 - 5pz
- B. 2sp3 - 3pz
- C. 2sp3 - 2pz
- D. 2sp3 - 4pz
Explanation: In the compound CH3 - CH2 - CH2 - Br , As we know that Br lies in 4th period so Bromine has 4pz orbital.
Correct answer: 2sp3 - 4pz- A. (CH3)2CHCH2Cl
- B. (CH3)3CCl
- C. Both
- D. None of the above
Explanation: Option B is correct.The product formed in excess in the chlorination of isobutane is 2-chloro-2-methylpropane.
Correct answer: (CH3)3CCl- A. Halogenation of alkane
- B. ROH and PX3
- C. ROH and HX
- D. Alkene and HX
Explanation: Option B is correct.ROH and PX3 is not a suitable method for the preparation of alkyl halide.
Correct answer: ROH and PX3- A. o-Bromotoluene
- B. p-Bromotoluene
- C. Benzylbromide
- D. Mixture of (1) & (2)
Explanation: Option C is correct. Toluene on treatment with one equivalent of bromine in the presence of light produces benzyl bromide as the major…
Correct answer: Benzylbromide- A. CH3CI
- B. C2H4CI2
- C. CH2CI2
- D. All of these
Explanation: Option D is correct. CH3Cl, C2H4Cl2, and CH2Cl2 are all alkyl halides. An alkyl halide is an organic compound that contains a carbon atom…
Correct answer: All of these- A. CH2CI2
- B. CH3CH3CH2CI
- C. CHCI3
- D. CCI4
Explanation: Option B is correct.Monohalo alkanes have only one halogen attached to hydrocarbon chain and follow general formula CnH2n+1X.
Correct answer: CH3CH3CH2CI- A. Iso-propyl halide
- B. Sec. butyl halide
- C. Ter. butyl halide
- D. Neo-pentyl halide
Explanation: Option A is correct.Isopropyl halide is a primary alkyl halide. An alkyl halide is an organic compound that has a halogen atom attached to…
Correct answer: Iso-propyl halide