In the chlorination of isobutane, which product will be formed in excess:
Correct answer: B. (CH3)3CCl
- A. (CH3)2CHCH2Cl
- B. (CH3)3CCl
- C. Both
- D. None of the above
Explanation
Option B is correct.The product formed in excess in the chlorination of isobutane is 2-chloro-2-methylpropane. The reaction can be represented by the following equation: (CH3)3C + Cl2 → (CH3)3CCl + HCl In this reaction, the isobutane molecule is attacked by a chlorine molecule, forming a chloroisobutane molecule and a hydrogen chloride molecule. The chloroisobutane molecule can then be attacked by another chlorine molecule, forming 2-chloro-2-methylpropane. The 2-chloro-2-methylpropane is the most stable product of the reaction, so it is formed in excess
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About Alkyl Halides
Alkyl halides are named and related to their carbon-halogen structure, polarity and reactivity. The key reactions are nucleophilic substitution by SN1 and SN2 mechanisms and elimination by E1 and E2 mechanisms, including how substrate structure, nucleophile, base, solvent and temperature influence substitution versus elimination.
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