Free Inheritance MCQs with Answers
1,238 Inheritance MCQs from Biology, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Mendel's laws explain segregation, independent assortment and the prediction of genetic ratios using alleles, genotypes and phenotypes. The chapter also covers linked genes, recombination and crossing over during meiosis, then applies pedigree reasoning to X-linked recessive traits, which show different inheritance patterns in males and females.
Last updated
Read the Inheritance notesFree MDCAT chapter notes with key terms1,238 questions · page 8 of 62
- A. Homozygous recessive alleles
- B. Homozygous dominant alleles
- C. Heterozygous dominant alleles
- D. Heterozygous recessive alleles
Explanation: Dwarf plants appear only when both alleles are recessive (tt), i.e homozygous recessive.
Correct answer: Homozygous recessive alleles- A. 1:3
- B. 3:9
- C. 3:1
- D. 9:3
Explanation: The phenotypic ratio in a monohybrid cross is 3 dominant : 1 recessive, so recessive to dominant = 1:3.
Correct answer: 1:3- A. Monohybrid cross
- B. Test cross
- C. Dihybrid cross
- D. None of these
Explanation: A test cross involves crossing with a homozygous recessive to reveal the unknown genotype of another plant.
Correct answer: Test cross- A. 3:1
- B. 1:3
- C. 1:2:1
- D. 4:0
Explanation: Crossing Tt × Tt yields genotypes TT, Tt, Tt, tt, giving a ratio of 1:2:1.
Correct answer: 1:2:1- A. 3/16 tall, round: 3/16 dwarf, wrinkled
- B. 9/16 tall, round : 1/16 dwarf, round
- C. 9/16 tall, wrinkled: 3/16 dwarf, round
- D. 3/16 tall, wrinkled; 3/16 round dwarf
Explanation: In a dihybrid cross, the phenotypic ratio is 9:3:3:1, which includes 3/16 tall wrinkled and 3/16 round dwarf.
Correct answer: 3/16 tall, wrinkled; 3/16 round dwarf- A. Synapse
- B. Crossing over
- C. Independent assortment
- D. Both b and c
Explanation: Mendel studied traits on different chromosomes, where crossing over and independent assortment prevented linkage.
Correct answer: Both b and c- A. Round and yellow seeds
- B. Wrinkled and yellow seeds
- C. Round and green seeds
- D. Wrinkled and green seeds
Explanation: All F₁ plants are RrYy, expressing the dominant traits → round and yellow seeds..
Correct answer: Round and yellow seeds- A. 1/16
- B. 3/16
- C. 2/16
- D. 4/16
Explanation: In a dihybrid cross, only 1/16 offspring are double recessive (rryy), giving wrinkled green seeds.
Correct answer: 1/16- A. 2
- B. 1
- C. 3
- D. 4
Explanation: Only RRyy plants are homozygous round with green seeds, appearing in 1/16 of progeny.
Correct answer: 1- A. 50% purple , 50% white
- B. All white
- C. 30% white , 70% purple
- D. All purple
Explanation: Purple is dominant over white, so F₁ offspring (Pp) all show purple flowers.
Correct answer: All purple- A. Different alleles expressed in heterozygous condition
- B. Complete dominance of one allele
- C. Phenotype of heterozygote is intermediate
- D. Gene mutation produces alleles
Explanation: In incomplete dominance, heterozygotes show a blended phenotype (intermediate between homozygotes).
Correct answer: Phenotype of heterozygote is intermediate- A. Genetic drift
- B. Natural selection
- C. Mutation
- D. Non-random mating
Explanation: Mutations in DNA create new alleles, introducing genetic variation in populations.
Correct answer: Mutation- A. Multiple allelism
- B. Co-dominance
- C. Complete dominance
- D. Gene linkage
Explanation: ABO blood group is controlled by three alleles (IA, IB , i) is an example of multiple allelism.
Correct answer: Multiple allelism- A. Have one allele
- B. Have no alleles
- C. Have two of them
- D. None of these
Explanation: Diploid organisms inherit two alleles for each gene (one from each parent), even if more alleles exist in the population.
Correct answer: Have two of them- A. Complete dominance
- B. Mutation
- C. Sex linkage
- D. Gene linkage
Explanation: The ABO system arose from mutations in the "I" gene, producing IA , IB , and i alleles.
Correct answer: Mutation- A. Option A
- B. Option A and B
- C. Option C
- D. Option D
Explanation: Blood group A can be IᴬIᴬ (homozygous) or Iᴬi (heterozygous), since A is dominant over O.
Correct answer: Option A and B- A. Blood group A
- B. Blood group AB
- C. Blood group B
- D. Blood group O
Explanation: Presence of B antigen on RBCs with anti-A antibodies in plasma defines group B.
Correct answer: Blood group B- A. A and B groups only
- B. A and O groups only
- C. AB only
- D. All four groups
Explanation: Mother A can be IᴬIᴬ ,or Iᴬi; father is O can be ii. Offspring genotypes are Iᴬi (type A) or ii (type O).
Correct answer: A and O groups only- A. Six
- B. Four
- C. Three
- D. Five
Explanation: IA , IB and i give six genotypes but phenotypes collapse to A, B, AB, O - so 4 observable blood types (IA and IB are codominant; i is…
Correct answer: Four160. Which of the following blood groups is not possible in a person whose father is of blood group O?
- A. AB
- B. B
- C. A
- D. O
Explanation: Father O = ii can only pass i. AB requires one IA and one IB allele that is impossible if one parent contributes only i.
Correct answer: AB