Free Inheritance MCQs with Answers
1,238 Inheritance MCQs from Biology, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Mendel's laws explain segregation, independent assortment and the prediction of genetic ratios using alleles, genotypes and phenotypes. The chapter also covers linked genes, recombination and crossing over during meiosis, then applies pedigree reasoning to X-linked recessive traits, which show different inheritance patterns in males and females.
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- A. 20
- B. 60
- C. 30
- D. 80
Explanation: The recombination frequency is 20% between the two genes. The distance between them in the unit map is 20.
Correct answer: 20- A. BCAD
- B. CBAD
- C. ACBD
- D. ABCD
Explanation: A pair of genes with a larger recombination frequency are likely farther apart, while a pair with a smaller recombination frequency is…
Correct answer: CBAD- A. 23
- B. 21
- C. 24
- D. 22
Explanation: Humans have 22 pairs of autosomes and 1 pair of sex chromosomes.
Correct answer: 22- A. 22
- B. 46
- C. 23
- D. 80
Explanation: Number of linkage group is equal to number of homologous chromosomes in a cell. There are 23 linkage groups in human cells.
Correct answer: 23- A. Random fusion of gametes
- B. Crossing over
- C. Gene linkage
- D. Mutation
Explanation: Gene linkage does not obey Mendel's law of independent assortment. Hence the chances of variation and genetic recombination are reduced.
Correct answer: Gene linkage- A. Sister chromatids of homologous chromosomes
- B. Non-sister chromatids of homologous chromosomes
- C. Non-sister chromatids of non-homologous chromosomes
- D. Sister chromatids of non-homologous chromosome
Explanation: B is correct. As the homologous chromosomes line up during meiosis, an exchange of segments between non-sister chromatids occurs.
Correct answer: Non-sister chromatids of homologous chromosomes- A. Eight
- B. One less than the pairs of chromosomes
- C. Four
- D. One more than the pairs of chromosomes
Explanation: Number of linkage groups in an organism is equal to number of chromosomal pairs.Hence 4 chromosomal pairs means it has 4 linkage groups.
Correct answer: Four- A. Sutton
- B. Fleming
- C. Morgan
- D. Landsteiner
Explanation: Before Morgan there was speculation about role of chromosomes in inheritance but no one had proved it experimentally.
Correct answer: Morgan- A. Hemophilia
- B. Color blindness
- C. Phenylketonuria
- D. Epilepsy
Explanation: Hemophilia, colorblindness, and Phenylketonuria diseases are genetic disorders.
Correct answer: Epilepsy- A. Hemophilia A
- B. Testicular feminization syndrome
- C. Hemophilia B
- D. Hypophosphatemia
Explanation: Testicular feminization syndrome is a rare X-linked recessive trait. Similarly, Haemophilia is also X-linked recessive.However,iIn most…
Correct answer: Hypophosphatemia- A. Hemophilia A
- B. Hemophilia C
- C. Hemophilia B
- D. TFM syndrome
Explanation: Haemophilia A and B are non-allelic recessive sex-linked but hemophilia C is an autosomal recessive trait (Autosome 4).
Correct answer: Hemophilia C- A. The zigzag pattern of inheritance
- B. Passes directly from father to son
- C. Rhodopsin
- D. More common in men
Explanation: Like any sex-linked recessive traits, colorblindness also moves zigzags from maternal grandfather through a carrier daughter to a grandson.
Correct answer: Passes directly from father to son- A. 0%
- B. 50%
- C. 25%
- D. 75%
Explanation: Out of 4 children 1 son and 1 daughter would be haemophilic, 1 daughter can be a carrier and 1 son completely normal.
Correct answer: 50%- A. Hypophosphatemia
- B. Haemophilia
- C. Vitamin-D resistant rickets
- D. Diabetes mellitus
Explanation: Haemophilia and colour blindness are X-linked recessive traits.
Correct answer: Haemophilia- A. Male pattern baldness
- B. Haemophilia
- C. Diabetes mellitus
- D. Erythroblastosis fetalis
Explanation: Haemophilia and colour blindness are X-linked recessive traits.
Correct answer: Haemophilia- A. Y-chromosome
- B. Autosome No. 7
- C. X-chromosome
- D. Autosome No.9
Explanation: The genes for red and green opsins are on X chromosome while the gene for blue opsin is present on autosome 7.
Correct answer: X-chromosome- A. 100% all females and males will be haemophiliac
- B. Canier female 25% haemophilic female 25%, 25% normal male and 25% haemophilic male
- C. Females and males both have 50% chances to getting haemophilia
- D. Females have 50% chances of getting haemophilia and females will be 100% haemophilic
Explanation: Out of 4 children 1 son and 1 daughter would be haemophilic, 1 daughter can be a carrier and 1 son completely normal.
Correct answer: Canier female 25% haemophilic female 25%, 25% normal male and 25% haemophilic male- A. X linked dominant traits
- B. Y linked inheritance
- C. X linked recessive traits
- D. Pseudoautosomal traits
Explanation: Haemophilia A and B, color blindness are the example of X-Linked recessive Traits.
Correct answer: X linked recessive traits- A. Monochromacy
- B. Protanopia
- C. Tritanopia
- D. Deuteranopia
Explanation: Protanopia is red color blindness. Deuteranopia is green color blindness. Tritanopia is blue color blindness
Correct answer: Deuteranopia- A. Gout
- B. Duchenne muscular dystrophy
- C. Testicular feminization syndrome
- D. Color blindness
Explanation: Tfn gene encodes a receptor for a hormone known as androgen. Androgens are unable to bind to receptors when the mutated tfm gene fails to…
Correct answer: Testicular feminization syndrome