Moderate

Which compound forms K2Cr2O7?

Correct answer: C. n-Propyl benzene

  • A. Toluene
  • B. Ethyl benzene
  • C. n-Propyl benzene
  • D. All

Explanation

In the presence of K2Cr2O7 (potassium dichromate), only alkyl side chains that are benzylic (next to a benzene ring) or allylic can be oxidized. Among the given options, n-Propyl benzene contains a propyl group attached to a benzene ring, making it capable of forming K2Cr2O7

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About Chemistry of Hydrocarbons

Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.

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