When different alkenes are treated with hot concentrated KMnO4 solution, different products are obtained. Which of the following alkenes produces two moles of carboxylic acids?
Correct answer: C. R1R2C = CR3R4
- A. H2C = CH2
- B. R - CH = CH - R
- C. R1R2C = CR3R4
- D. R1R2C = CHR4
Explanation
When a symmetrical alkene like R1R2C=CR3R4 is treated with hot concentrated KMnO4, it undergoes oxidative cleavage to produce two moles of carboxylic acids. The reaction breaks the double bond between the two carbons, and each carbon becomes part of a carboxylic acid functional group (-COOH).
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Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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