When 20J of work was done on a gas, 40J of heat energy was released If the initial internal energy of the gas was 70J. what is the final internal energy?
Correct answer: A. 50J
- A. 50J
- B. 60J
- C. 90J
- D. 110J
Explanation
The change in internal energy is 20-40 = -20 J so the final internal energy is x where x-70= -20X=50
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About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
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