A carnot engine working between 200k and 400k has a work output of 600 J per cycle. How much heat energy is supplied to the engine from the source of each cycle.
Correct answer: B. 1200 J
- A. 1400 J
- B. 1200 J
- C. 1700 J
- D. 1300 J
Explanation
T₁ =400kT₂-200kW=800JWe know efficiency=1-T2/T1-WW/Q=1-200/400=600/0.5=1200JAs it is numerical, it can have only one answer.
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About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
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