When 2Ω, 4Ω and 6Ω resistor are connected in parallel their resultant equivalent resistance will be?
Correct answer: C. 12/11Ω
- A. 12Ω
- B. 11/12Ω
- C. 12/11Ω
- D. None
Explanation
To find the equivalent resistance of resistors in parallel, we use the formula: 1/Req = 1/R1 + 1/R2 + 1/R3. Given R1= 2Ω, R2= 4Ω, and R3 = 6Ω, we calculate:1/Req = 1/2 + 1/4 + 1/6 = 6/12 + 3/12 + 2/12 = 11/12Taking the reciprocal gives us Req = 12/11Ω. This makes Option C correct.Option A (12Ω) is incorrect because it assumes a series connection, not parallel. Option B (11/12Ω) is the reciprocal of the correct result, thus incorrect. Option D (None) is incorrect because there is a definitive equivalent resistance value.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Current Electricity
Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
Practise Current Electricity
1,052 free Current Electricity MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.