When 2Ω, 4Ω and 6Ω resistor are connected in parallel their resultant equivalent resistance will be?
Correct answer: C. 12/11Ω
- A. 12Ω
- B. 11/12Ω
- C. 12/11Ω
- D. None
Explanation
To find the equivalent resistance of resistors in parallel, we use the formula: 1/Req = 1/R1 + 1/R2 + 1/R3. Given R1= 2Ω, R2= 4Ω, and R3 = 6Ω, we calculate:1/Req = 1/2 + 1/4 + 1/6 = 6/12 + 3/12 + 2/12 = 11/12Taking the reciprocal gives us Req = 12/11Ω. This makes Option C correct.Option A (12Ω) is incorrect because it assumes a series connection, not parallel. Option B (11/12Ω) is the reciprocal of the correct result, thus incorrect. Option D (None) is incorrect because there is a definitive equivalent resistance value.
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