A wire has a resistance of 5.5 0 at 19oC and 21.5 0 at 200oC. Find the temperature coefficient of resistivity(a) of the material.

Explanation

To find the temperature coefficient of resistivity (α) of the material, we can use the formula:α = (R2 - R1) / (R1 * (T2 - T1))Where: α is the temperature coefficient of resistivity, R1 is the resistance at temperature T1, R2 is the resistance at temperature T2, T1 is the initial temperature, and T2 is the final temperature.Given: R1 = 5.5 Ω (at 19°C) R2 = 21.5 Ω (at 200°C) T1 = 19°C T2 = 200°CUsing the formula, we can calculate α:α = (21.5 Ω - 5.5 Ω) / (5.5 Ω * (200°C - 19°C))Simplifying the equation:α = 16 Ω / (5.5 Ω * 181°C) α ≈ 0.016 °C^(-1) or 1.6 * 10^(-2) °C^(-1).As this is a numerical thus only one option is correct.