Maximum power delivered by battery is
Correct answer: A. Pmax= E2/4r
- A. Pmax= E2/4r
- B. Pmax = 4rE2
- C. Pmax = VIT
- D. Unlimited
Explanation
It states that the output power of a source of current is maximum, when the internal resistance of the source is equal to the external resistance in the circuit. So, if R is the external resistance of the circuit and r is the internal resistance of the source of current (i.e. a battery) then the output power is maximum, when R = r.This theorem is applicable to all types of source of e.m.f. and is related with the output power and NOT with the power dissipated.If E is the applied e.m.f. of the source of e.m.f. i.e. a battery of internal resistance r and R is the external resistance then current in the circuit is given as:I = E/(R + r)At the maximum output power, R = r, so we have:I = E/(r + r) = E/(2r) and maximum output power:Pmax = I2r = E2/(4r)
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About Current Electricity
Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
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