What will be the pressure of 1 mole of an ideal gas maintained at 300 K and 250cm3 volume ?
Correct answer: A. 98.5 atm
- A. 98.5 atm
- B. 96.7 atm
- C. 95.8 atm
- D. 97.1 atm
Explanation
Using PV = nRT, P = nRT/V = (1 mol)(0.0821 L atm K^-1 mol^-1)(300 K)/(0.250 L) = 98.52 atm, which rounds to 98.5 atm. The likely mistake is choosing 96.7 atm or another nearby value from using 250 cm3 as 250 L instead of converting it to 0.250 L.
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About Ideal Gas Equation
The ideal gas equation, PV = nRT, relates pressure, volume, amount and absolute temperature when gas particles are assumed to have negligible volume and no intermolecular forces. Applications include finding molar mass, density or an unknown gas variable, with careful use of Kelvin temperature and consistent units, and comparison with real-gas behaviour.
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