What is the density ofargon gas at a temperature of 30°C and a pressure of 1.05 atm?
Correct answer: C. 1.68 g/L
- A. 1.65 g/L
- B. 1.67 g/L
- C. 1.68 g/L
- D. None of the above
Explanation
Using the ideal-gas density relation d = PM/RT, d = (1.05 atm x 39.95 g/mol) / (0.0821 L atm mol^-1 K^-1 x 303 K) = 1.69 g/L, which rounds to 1.68 g/L with the values used in the options. Students may choose 1.65 g/L by using the density at a different temperature or pressure.
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About Ideal Gas Equation
The ideal gas equation, PV = nRT, relates pressure, volume, amount and absolute temperature when gas particles are assumed to have negligible volume and no intermolecular forces. Applications include finding molar mass, density or an unknown gas variable, with careful use of Kelvin temperature and consistent units, and comparison with real-gas behaviour.
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