One mole of an ideal gas at 546.5 K under 2 atm pressure has a volume of________________?
Correct answer: C. 22.414 dm3
- A. 22.414 m3
- B. 44.828 dm3
- C. 22.414 dm3
- D. 11.212 cm3
Explanation
Apply PV = nRT: V = nRT/P = (1 mol x 0.082057 L atm mol-1 K-1 x 546.5 K)/(2 atm) = 22.414 L. Since 1 L = 1 dm3, the volume is 22.414 dm3. Students may choose b by forgetting to divide by the pressure of 2 atm.
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About Ideal Gas Equation
The ideal gas equation, PV = nRT, relates pressure, volume, amount and absolute temperature when gas particles are assumed to have negligible volume and no intermolecular forces. Applications include finding molar mass, density or an unknown gas variable, with careful use of Kelvin temperature and consistent units, and comparison with real-gas behaviour.
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