What volume of oxygen is required for the complete combustion of a mixture of 5cm3 of CH4 and 5cm3 of C2H4?
Correct answer: D. 25 cm3
- A. 10 cm3
- B. 15 cm3
- C. 20 cm3
- D. 25 cm3
Explanation
CH4 + 2O2 → CO2 + 2H2O C2H4 + 3O2 → 2CO2 + 2H2O In these reactions, 1 mole of CH4 requires 2 moles of oxygen and 1 mole of C2H4 requires 3 moles of oxygen. So, the volume of oxygen required for the complete combustion of a mixture of 5 cm3 of CH4 and 5 cm3 of C2H4 is:5 cm3 CH4 * 2 moles O2 / 1 mole CH4 + 5 cm3 C2H4 * 3 moles O2 / 1 mole C2H4 = 25 cm3 O2.
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