What volume of oxygen is required for the complete combustion of a mixture of 5cm3 of CH4 and 5cm3 of C2H4?
Correct answer: D. 25 cm3
- A. 10 cm3
- B. 15 cm3
- C. 20 cm3
- D. 25 cm3
Explanation
CH4 + 2O2 → CO2 + 2H2O C2H4 + 3O2 → 2CO2 + 2H2O In these reactions, 1 mole of CH4 requires 2 moles of oxygen and 1 mole of C2H4 requires 3 moles of oxygen. So, the volume of oxygen required for the complete combustion of a mixture of 5 cm3 of CH4 and 5 cm3 of C2H4 is:5 cm3 CH4 * 2 moles O2 / 1 mole CH4 + 5 cm3 C2H4 * 3 moles O2 / 1 mole C2H4 = 25 cm3 O2.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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