Determine the number of moles of oxygen in 10.6g of Na2CO3
Correct answer: B. 0.3 moles
- A. 0.4 moles
- B. 0.3 moles
- C. 0.2 moles
- D. None of these
Explanation
Molar mass of Na2CO3 = 106 g/mole Moles of Na2CO3 in 10.6g = mass/molar mass = 10.6g/106 g/mole = 0.1 moles. From the chemical formula of Na2CO3 we can see that there are 3 moles of oxygen for every mole of Na2CO3. So, moles of oxygen =0.1 mole X 3 = 0.3 moles. Therefore, there are 0.3 moles of oxygen in 10.6g of Na2CO3.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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