Two cells of emf 6 V and 4 V, each with internal resistance 1 Ω. are connected in series with an external resistor of 5 Ω. The current in the circuit is:
Correct answer: B. 1.5A
- A. 0.5A
- B. 1.5A
- C. 3A
- D. 2A
Explanation
Total emf = 6 + 4 = 10 V. Total resistance = 1 + 1 + 5 = 7 Ω. Current I = E/Rₜₒₜₐₗ = 10/7 ≈ 1.43 A, closest to 1.5 A.
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About Current Electricity
Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
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