A potentiometer wire of length 1 m has a resistance of 10 Ω. A cell of emf 2 V is connected across it. The potential gradient along the wire is:
Correct answer: B. 2 V/m
- A. 0.2 V/m
- B. 2 V/m
- C. 0.02 V/m
- D. 1 V/m
Explanation
Current I = V/R = 2/10 = 0.2 A. Potential drop across the wire = 2 V. Potential gradient = V/L = 2/1 = 2 V/m.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Current Electricity
Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
Practise Current Electricity
1,052 free Current Electricity MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Current Electricity questions
Two cells of emf 6 V and 4 V, each with internal resistance 1 Ω. are connected in series with an external resistor of 5 Ω. The current in the circuit is:
A 60 W bulb is designed for 120 V. If connected to a 240 V supply, the power consumed is:
A wire has resistance 12 Ω. If it is bent into a circle and two points diametrically opposite are connected, the equivalent resistance between them is:
A circuit with a 10 V battery and resistors 2 Ω and 3 Ω in series is connected in parallel with a 5 Ω resistor. The total current from the battery is:
A 100 Ω resistor and a 200 Ω resistor are connected in series with a 12 V battery. The potential difference across the 200 Ω resistor is:
In a circuit, three resistors of 2 Ω, 3 Ω, and 6 Ω are connected in parallel across a 12 V battery with internal resistance 1 Ω. The current through the 3 Ω resistor is: