To neutralize completely 20 mL of 0.1M aqueous solution of phosphorous acid H3PO3 , the value of 0.1M aqueous KOH solution required is:
Correct answer: A. 40 mL
- A. 40 mL
- B. 20 mL
- C. 10 mL
- D. 60 mL
Explanation
N1V1=N2V2 (H3PO3 is dibasic ; M = 2N)20 x 0.2 = 0.1 x VV = 40 ml
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