In an aqueous solution of barium nitrate, the [NO-3] is 0.080M. This solution can be labeled as:
Correct answer: C. 0.080 N Ba(NO3)2
- A. 0.040 N Ba(NO2)2
- B. 0.160 M Ba(NO3)2
- C. 0.080 N Ba(NO3)2
- D. 0.080 M NO-3
Explanation
In Ba3(NO3)2, the molar ratio of Ba(NO3)2 to NO-3 is 1 : 2. Therefore, the molarity of the Ba(NO3)2 solution is: 1/2 x 0.0080=0.040M As n − factor of Ba(NO3)2 is 2, its Normality will be 0.080 N.
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