There is a total of 800 mA of current into four parallel resistors. The currents through three of the resistors are 40 mA, 70 mA, and 200 mA. The current through the fourth resistor is______________?
Correct answer: A. 490 mA
- A. 490 mA
- B. 800 mA
- C. 310 mA
- D. 0 A
Explanation
By Kirchhoff's current law, the branch currents must add to the total: 40 + 70 + 200 = 310 mA. The fourth branch therefore carries 800 - 310 = 490 mA.
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