Four resistors are connected in parallel. Fifteen mA flows through resistor R. If the second resistor is 2R, the third resistor 3R, and the fourth resistor 4R, the total current in the circuit is______________?
Correct answer: D. 31.25 mA
- A. 60 mA
- B. 15 mA
- C. 135 mA
- D. 31.25 mA
Explanation
All parallel resistors have the same voltage, so branch current is inversely proportional to resistance. The currents are 15, 7.5, 5, and 3.75 mA, giving a total of 31.25 mA.
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