The following currents are measured in the same direction in a three-branch parallel circuit: 200 mA, 340 mA, and 700 mA. The value of the current into the junction of these branches is____________?
Correct answer: C. 1.24 A
- A. 200 mA
- B. 540 mA
- C. 1.24 A
- D. 900 mA
Explanation
If all three listed branch currents are directed into the junction, Kirchhoff's current law gives 200 + 340 + 700 = 1240 mA, or 1.24 A. The wording assumes the stated common direction is toward the junction.
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