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The volume of 𝐢𝑂2 produced by heating 33.5𝑔 𝐿𝑖2𝐢𝑂3 at room temperature and pressure is (π‘€π‘Ÿ 𝐿𝑖2𝐢𝑂3 = 67𝑔/π‘šπ‘œπ‘™):

Correct answer: B. 12.0 π‘‘π‘š3

  • A. 22.4 π‘‘π‘š3
  • B. 12.0 π‘‘π‘š3
  • C. 11.2 π‘‘π‘š3
  • D. 24.0 π‘‘π‘š3

Explanation

moles of Li2CO3= mass/Mr =33.5/67 = 0.5 Moles of CO2: moles of Li2CO3 1 : 1 Hence moles of CO2 =0.5 0.5 Γ— 24= 12dm3 Molar volume at ROOM temperature and pressure is 12 dmΒ³ while molar volume at STANDARD temperature and pressure is 22.4 dmΒ³.

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About Fundamental Concepts of Chemistry

Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.

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