Ethanol C2H5OH is the substance commonly called "alcohol". The density of liquid ethanol is 0.7893 gml-1 at 20°C. If 1.2 mol of ethanol is needed for a particular experiment, what volume of ethanol should be measured?
Correct answer: C. 70ml
- A. 55ml
- B. 58ml
- C. 70ml
- D. 79ml
Explanation
ρ=0.7893g/ml n=1.2 mole The molar mass of ethanol= 46 Weight of ethanol=? Volume=? n=WeighT/Molarmass =Weight/46 ⇒1.2×46=Weight ⇒55.2g=Weight ρ=Volumeweight =55.2 /0.7893 =Volume Volume=69.9ml≈70ml
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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