Calculate the grams of H2O formed when 8g of CH4 burns in excess of oxygen:
Correct answer: C. 18 grams
- A. 21 grams
- B. 19 grams
- C. 18 grams
- D. 15 grams
Explanation
8/16 = 0.5 mol of CH4 1 mole of CH4 yields 2 moles of H2O, so 0.5 mole will yield 1 mole of H2O. Mass = mol x Mr = 18 x 1 = 18g Hence, option C is the only right answer.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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