The value of pressure and volume of fixed mass of gas in thermometer at triple point of water Pf=1.00 x 10^5 Pa and Vf=1 x 10^-3 m³. When P=1.1 x 10^5 Pa and V=1.2 x 10^-3 m³. Then temperature of gas is:
Correct answer: A. 361K
- A. 361K
- B. 298K
- C. 273K
- D. 250K
Explanation
For a fixed mass of gas the thermometer relation is T = T_triple x (PV)/(Pf Vf), with the triple point of water at 273.16 K. So T = 273.16 x (1.1 x 10^5 x 1.2 x 10^-3)/(1.0 x 10^5 x 1.0 x 10^-3) = 273.16 x 1.32 = 361 K.
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