Asked in ETEA MDCAT 2009 2009Moderate

Pressure exerted by perfect gas is equal to :

Correct answer: C. ⅔ mean K.E/volume

  • A. ⅓ mean K.E/volume
  • B. ½ Mean K.E/volume
  • C. ⅔ mean K.E/volume
  • D. Mean K.E/volume

Explanation

Starting from PV = (1/3)Nm<v^2> and writing the mean kinetic energy per molecule as (1/2)m<v^2>, the pressure becomes P = (2/3) x (total mean kinetic energy / volume). The factor of 2/3 is what converts the (1/3)m<v^2> term into the (1/2)m<v^2> of kinetic energy.

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Thermal equilibrium and heat explain how temperature and energy transfer are related, while molar specific heats describe the heat required by a gas at constant volume or constant pressure. The first law connects heat supplied, work done and change in internal energy, with sign conventions kept distinct from temperature changes.

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