The oxidation state of carbon in Na2C2 is:
Correct answer: C. -1
- A. +4
- B. +2
- C. -1
- D. -4
Explanation
We know that the charge of Na is always +1, and the overall charge on the Na2C2 molecule is 0. We can equate this to form2(+1) + 2x = 02x = -2x(Charge on C) = -1
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About Oxidation and Reduction
Oxidation involves loss of electrons, increase in oxidation number or addition of oxygen, while reduction involves electron gain, decrease in oxidation number or removal of oxygen. The topic covers oxidising and reducing agents, oxidation-number changes, redox equations and the distinction between oxidation at the anode and reduction at the cathode.
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