The order of reducing power of halide ion is:
Correct answer: A. I-1> Br->Cl-> F-
- A. I-1> Br->Cl-> F-
- B. F->Cl-> Br-> l-
- C. l-1>Cl-> F-> Br-
- D. Br->Cl-> l-> F-
Explanation
From the reduction potential values, it can be seen that iodide is the best-reducing agent. It has a low reduction potential value which indicates that it easily reduces others and itself gets oxidized.
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About Oxidation and Reduction
Oxidation involves loss of electrons, increase in oxidation number or addition of oxygen, while reduction involves electron gain, decrease in oxidation number or removal of oxygen. The topic covers oxidising and reducing agents, oxidation-number changes, redox equations and the distinction between oxidation at the anode and reduction at the cathode.
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