The oxidation state of carbon in C2O42- is:
Correct answer: C. +3
- A. +4
- B. -4
- C. +3
- D. +2
Explanation
The oxidation number is the apparent charge on an atom of an element in a molecule or ion. It may be positive, negative, or zero. The rules for calculating oxidation number are as follows: Considering all the rules here, particularly point numbers (iv) and (vi), let us assume that the oxidation number of carbon is x, so the equation that we get is: 2x + 4(-2) = -2 2x - 8 = -2 2x= 6 x= +3 Hence the oxidation number of C in oxalate ions is +3, therefore, the correct answer is option C.
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Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
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