The number of water molecules present in a drop of water weighing 0.018 gm is 6.023 × __________?
Correct answer: C. 1020
- A. 1026
- B. 1023
- C. 1020
- D. 1019
Explanation
Water weighing 0.018 g contains 0.018/18 = 0.001 mol. Multiplying by Avogadro’s number gives 6.023 × 10²⁰ molecules.
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