The amount of Zn (atomic weight = 65) required to form 224 c.c. of H2 at N.T.P. on treatment with dilute H2SO4will be _____________ gm?
Correct answer: B. 0.65
- A. 0.065
- B. 0.65
- C. 6.5
- D. 65
Explanation
At NTP, 224 cc of hydrogen represents 224/22400 = 0.01 mol H₂. The zinc-to-hydrogen molar ratio is 1:1, so the required zinc mass is 0.01 × 65 = 0.65 g.
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