In the reaction, Ca + 2H2O = Ca(OH)2 + H2; what volume (c.c.) of hydrogen at STP would be liberated, when 8 gm of calcium reacts with excess water ? (Atomic weight of calcium = 40) ?
Correct answer: A. 4480
- A. 4480
- B. 2240
- C. 1120
- D. 0.4
Explanation
Eight grams of calcium represents 8/40 = 0.2 mol, and the stoichiometry gives 0.2 mol of hydrogen. At STP, this occupies 0.2 × 22,400 = 4,480 cc, so option a follows.
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