The hydrolysis of an ester in presence of an alkali (NaOH) is known as:
Correct answer: C. Saponification
- A. Esterificatoon
- B. Decarboxylation
- C. Saponification
- D. Transesterification
Explanation
Saponification is the process of hydrolyzing an ester in the presence of an alkali, typically sodium hydroxide (NaOH).
This question appeared on the KMU Centralized Admission Test 2020 paper, which you can sit online with every answer explained.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Carboxylic Acid Derivatives
Carboxylic acid derivatives include acid halides, acid anhydrides, esters and amides, formed by replacing the hydroxyl group of a carboxylic acid. Their nomenclature, structures, preparation, hydrolysis and relative reactivity are linked through nucleophilic acyl substitution, which differs from the nucleophilic addition reactions of aldehydes and ketones.
Practise Carboxylic Acids
550 free Carboxylic Acids MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Carboxylic Acid Derivatives questions
Choose reactants whose reaction product is ester:
The hydrolysis of an ester proceeds most slowly under the conditions of:
Which is the correct formula for ammonium carbamate?
In conversion of acid halides to Ester, pyridine is used to:
The IUPAC name of formyl chloride is:
The formula CH3(CH2)16COO- Na+ represents a member of the class of compounds which are known as: