The electric potential at the surface of an atomic nucleus (Z=50) of radius 9.0x 10⁻¹⁵m is:
Correct answer: B. 8 x 10⁶ V
- A. 9V
- B. 8 x 10⁶ V
- C. 9 x 10⁵ V
- D. 80 V
Explanation
The total charge of the nucleus is Q = Ze = 50 × (1.6 × 10⁻¹⁹ C). The potential is V = kQ/r. V = (9 × 10⁹) × (50 × 1.6 × 10⁻¹⁹) / (9.0 × 10⁻¹⁵) = 8 × 10⁶ V.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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