A and B are two points in an electric field. If the work done in carrying 4.0 coulombs of electric charge from A to B is 16.0 joules, the potential difference between A and B is:
Correct answer: B. 4V
- A. Zero
- B. 4V
- C. 2.0 V
- D. 16V
Explanation
The potential difference (V) between two points is defined as the work done (W) per unit charge (q). V = W/q = 16.0 J / 4.0 C = 4 V.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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