Potential due to charge q at distance 1m is 5V, at distance 3m will be:
Correct answer: A. 5/3 V
- A. 5/3 V
- B. 7/3 V
- C. 3/5 V
- D. 3/7 V
Explanation
Electric potential (V) due to a point charge is inversely proportional to the distance (r) from the charge (V ∝ 1/r). If the distance increases by a factor of 3 (from 1m to 3m), the potential will decrease by a factor of 3, becoming 5/3 V.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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