The electric potential at the surface of an atomic nucleus (Z=50) of radius 9.0 x 10^-13m is:
Correct answer: B. 8 x 10^4 V
- A. 9V
- B. 8 x 10^4 V
- C. 9 x 10^5V
- D. 80 V
Explanation
We know that the elementary charge, e, is approximately 1.6 × 10-19 C. Therefore, the charge of the nucleus, Q, can be calculated as follows:Q = Z * e= 50 * (1.6 × 10-19 C)Q ≈ 8 × 10-18 CNow we can substitute the values into the formula for electric potential:V = (9 × 109 N m²/C²) * (8 × 10-18 C) / (9.0×10-13 m)By simplifying the expression, we find:V = 8 × 104 V (volts)
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