A capacitor with air as the dielectric is charged to a potential of 100 volts. If the space between the plate is now fillwed with a dielectric of dielectric constant 10, the potential difference between the plates will be

Explanation

When a dielectric material with a dielectric constant K is introduced into a capacitor, the capacitance C increases by a factor of K. For a charged capacitor, the potential difference V is inversely proportional to the capacitance, following the relationship Q = CV where Q is the charge. Here, the dielectric constant is 10, which means the capacitance increases tenfold, resulting in the potential difference dropping to 1/10 of its original value. Therefore, the new potential difference is 100 V / 10 = 10 V.Option A is incorrect because introducing a dielectric reduces the potential difference rather than increasing it. Option C is incorrect because it assumes the potential difference remains unchanged, which does not account for the dielectric's effect. Option D is incorrect as the potential difference cannot be zero unless the charge is also zero, which is not implied here.