Gauss's law is applied to calculate the:
Correct answer: A. Electric intensity due to different charge configurations
- A. Electric intensity due to different charge configurations
- B. Electric intensity due to positive charge only
- C. Electric intensity due to negative charge only
- D. None of these
Explanation
Gauss's law relates the electric flux through a closed surface to the charge enclosed by that surface. It is a versatile tool for calculating the electric field due to a variety of charge distributions, including positive, negative, or mixed charges. Option A accurately reflects this capability, as it encompasses the use of Gauss's law for different charge configurations. Options B and C are incorrect because Gauss's law applies to both positive and negative charges, not just one type. Option D is incorrect because Gauss's law is indeed used as described in Option A.
Last updated
About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
Practise Electrostatics
831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1/C_eq = 1/C_1 + 1/C_2 + 1/C_3 + ... + 1/C_n
1 N/C equals to:
1 volt x 1 ampere is equal to:
10 V potential difference is applied across the plate of the 1 µF capacitor. What is the energy stored in the capacitor?
12 J work is to be done against an existing electric field to take a charge of 0.01C from A to B. Find the potential difference between B and A: