Two thin infinite parallel plates have uniform charge densites +σ and -σ , the electric field in the space between them is:
Correct answer: C. σ /ϵ0
- A. σ /2ϵ0
- B. σ
- C. σ /ϵ0
- D. Zero
Explanation
According to Gauss's Law, for two infinite parallel plates with uniform charge densities +σ and -σ, the electric field between them is given by σ/ϵ0. The field is directed from the positively charged plate to the negatively charged plate. Option C is correct because it correctly applies Gauss's Law to the scenario described. Option A describes the field from a single plate, Option B omits the permittivity factor, and Option D incorrectly suggests the field is zero between the plates.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
Practise Electrostatics
831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electrostatics questions
The lines of force due to charge particles are:
Two metal plates have potential differences of 300 V and are 0.01 m apart. A charge particle of mass 1.96 x 10^-15 kg id held in equilibrium between the plates of the capacitor . Then the electric field is
Figure shows the electric lines of force emerging from a charged body. If the electron field at A and B are EA and Es respectively and if the displacement between A and B is then:
Gauss's law is applied to calculate the:
The capacity of a parallel plate capacitor is 5µF. When a glass plate is placed between the plates of the capacitor, its potential becomes1/8 of the orignal value. The value of dielectric constant will be
Two charged spheres of radii 10cm and 15cm are connected by a thin wire. No current will flow, if they have: