The diagram shows a galvanic cell. The current will flow from:
Correct answer: A. Hydrogen electrode to copper electrode
- A. Hydrogen electrode to copper electrode
- B. Copper electrode to hydrogen electrode
- C. Hydrogen electrode to HCl solution
- D. CuSO4 solution to hydrogen electrode
Explanation
The reduction potential of copper is greater than that of hydrogen so in that case, the copper electrode will act as a cathode and S.H.E will act as an anode so electrons will flow from S.H.E to the copper electrode Key point: S.H.E. acts as a cathode (gets reduced) when attached to an electrode of metal except for Cu, Ag,AU, and Pt.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Electrochemistry
Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
Practise Electrochemistry
696 free Electrochemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electrochemistry questions
Which one pair has the same oxidation state of 'Fe'?
Which one of the following is a redox reaction?
In the figure given below, the electron flow in external circuit is from:
For the purification, impure copper is made the:
The reducing agent in the reaction given, 𝐾𝑀𝑛𝑂4 + 𝐾𝐼 + 𝐻2𝑆𝑂4 ⟶ 𝑀𝑛𝑆𝑂4 + 𝐾2𝑆𝑂4 +𝐼2 + 𝐻2𝑂 is:
Students calculated the cell voltage for the reaction, 𝐵𝑟2 + 2𝑁𝑎𝐶𝑙 ⟶ 2𝑁𝑎𝐵𝑟 + 𝐶𝑙2 through the formula 𝐸°𝑐𝑒𝑙𝑙= 𝐸°𝑟𝑒𝑑+ 𝐸°𝑜𝑥𝑑 the answer was negative. It means that: