Moderate

In the figure given below, the electron flow in external circuit is from:

Correct answer: D. Zinc to copper electrode

  • A. Copper to zinc electrode
  • B. Right to left
  • C. Porous partition to zinc electrode
  • D. Zinc to copper electrode

Explanation

The electrons flow from the oxidation reaction (Zn (s) --> Zn2+ (aq) + 2 e-) to the reduction half-cell (Cu2+ (aq) + 2 e- --> Cu (s)). So the electrons flow from the left to the right (zinc to copper electrode).

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