The coulombs force between two point charges ,If magnitude of each charge is doubled and distance between charges is halved, the forces between them becomes:
Correct answer: D. 16F
- A. F
- B. 8F
- C. 4F
- D. 16F
Explanation
If the magnitude of each charge is doubled, then the force will be quadrupled. This is because the force is directly proportional to the product of the charges.If the distance between the charges is halved, then the force will be squared. This is because the force is inversely proportional to the square of the distance.So, if the magnitude of each charge is doubled and the distance between the charges is halved, then the force between them will be 16 times as great. F= Kq1q2/r2 q1'=2q1 q2'=2q2 r'=2r F'=k(2q1)(2q2)/(2r)2 F'= 16F
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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